(b) What is the physical significance of
van der Waals constant, ‘a’ and ‘b’.
Give their units.
Ans. (b) Physical Significance
of van der Waals constant ‘a’ and ‘b’
(i) Significance of’ a’:
The value of constant ‘a’ is a measure of the intermolecular attractive forces
and greater will be the ease of its liquefaction.
Units of ‘a’ :
The units of ‘a’ are related to the units of pressure, volume and number of
moles.
P=
or
a= =
a= atm dm6 mol-2
In SI
units:
a= ==Nm4 mole -2
(iii)
Significance of ‘b’: The value of
constant ‘b’ us related to the size of the molecule. Larger the size of the
molecule, lager is the value of ‘b’. It is effective volume of the gas
molecules.
Units of ‘b’:
‘b’ is the compressible volume
per mole of gas. So the units of ‘b’ are related to the units of volume and
moles.
V=nb
or b =
b==dm3
mol-1
In SI
units: b===dm3 mol-1
Q. Do you think that 1 mole of H2
and 1 mole NH3 at 0oC and 1 atm pressure will have
equal Avogadro’s number of particles? If not, why?
Justify
that 1 cm3 of H2 and 1 cm3 of CH4 at
STP will have the same number of molecules, when one molecules of CH4 is
8 times heavier than that of hydrogen.
Ans 1 mole of H2 and 1 mole of
NH3 at 0oC and 1 atm pressure will have equal number of
molecules under the same conditions of temperature and pressure. Hence, 1 cm3
of H2 and 1 cm3 of CH4 at STP will have the same number of molecules.
Q15. Explain the following
facts:
(a) The plot of PV versus P is a
straight line at constant temperature and with a fixed number of moles of an
ideal gas.
ans:
At constant temperature and with a fixed number of moles of an ideal gas, when the pressure of the gas is varied, its volume changes, but the product PV remains constant. Thus,
ans:
At constant temperature and with a fixed number of moles of an ideal gas, when the pressure of the gas is varied, its volume changes, but the product PV remains constant. Thus,
P1 V1 = P2 V2 = P3 V3
=
Hence, for any fixed temperature, the product PV when plotted against P.a
straight line parallel to P-axis is obtained. This straight line indicates that
PV remains constant quantity.
(b) The straight line in (a) is parallel to
pressure-axis and goes away from the pressure axis at higher pressure for many
gases.
ans:
ans:
Now, increase the temperature of the same from T1 to
T2 .At
constant temperature T2 and with the same fixed
number of moles
of an ideal gas, when the constant. However, the value of PV
increase with increase in temperature. On plotting graph
between P
on x-axis is obtained. This straight line at T2 will
be away from the
x-axis. This straight line also shows that PV is a constant
quantity.
(c) The van der walls constant ‘b’ of
a gas is four times the molar volume of that gas
Excluded volume, ‘b’ is four times the molar volume fo gas. The excluding with each other as shown in Fig. The spheres are considered to be non-compressible. So the molecules cannot approach each other more closely than the distance, 2r . Therefore, the space indicated by the dotted sphere having radius, 2r will not be available to all other molecules of the gas. In other words, the dotted spherical space is excluded volume per pair of molecules.
Excluded volume, ‘b’ is four times the molar volume fo gas. The excluding with each other as shown in Fig. The spheres are considered to be non-compressible. So the molecules cannot approach each other more closely than the distance, 2r . Therefore, the space indicated by the dotted sphere having radius, 2r will not be available to all other molecules of the gas. In other words, the dotted spherical space is excluded volume per pair of molecules.
Let each molecules be a sphere with
radius =r
Volume
of one molecules (volume of
sphere)=
The distance of the closest approach of 2
molecules =2 r
The
excluded volume for 2 molecules=
The excluded volume for 1 molecule=
=
=4Vm =b
The excluded volume for ‘n’ molecules=n b
Where Vm is the actual volume of a molecule.
Hence, the excluded volume or co-volume or non-compressible volume is equal to
4 times the actual volume of the molecules of the gas.
(d) Pressure of NH3
gas at given conditions (say 1 atm pressure and room temperature) is less
as calculated by van der Waals equation than that calculated by general gas
equation.
ans:
ans:
The pressure of NH3 calculated by general gas
equation is high
because it is considered as an ideal gas. In an ideal gas,
the
molecules do not exert any force of attraction on one
another. On
the other hand, when the pressure of NH3 is
considered as a real
gas. Actually, NH3 is a real gas. It consists of
polar NH3 molecules
approaches the walls of the container, it experiences an
inward
pull. Clearly, the molecule strikes the wall with a lesser
force than
it would have done it these are no attractive forces. As a
result of
this , the real gas pressure is less than the ideal
pressure.
(e) Water vapors do not behave ideally
at 273 k.
ans:
Water vapors present at 273K do not behave ideally because polar
ans:
Water vapors present at 273K do not behave ideally because polar
water molecules exert force of attraction on one another.
(f) SO2 is comparatively
non-ideal at 273 k but behaves ideally at
327 K.
ans:
At low temperature, the molecules of SO2 possess low kinetic energy. They come close to each other. The e intermolecular attractive forces become very high. So, it behave non-ideally at 273K. At high temperature, the molecules of SO2 have high kinetic energy. The molecules are at larger distances from one other another. The intermolecular attractive forces become very weak. So, it behaves ideally at 327K.
ans:
At low temperature, the molecules of SO2 possess low kinetic energy. They come close to each other. The e intermolecular attractive forces become very high. So, it behave non-ideally at 273K. At high temperature, the molecules of SO2 have high kinetic energy. The molecules are at larger distances from one other another. The intermolecular attractive forces become very weak. So, it behaves ideally at 327K.
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