37 % HCl Solution formation

Liquid Solution preparation procedure smile emoticon 
Mass of HCl = 37% x 100 g = 37 g 
Moles of HCl = mass/ Mr = 37 / ( 1.008+35.45) = 1.015 mol
Mass of water = mass of solution – mass HCl 
Mass of water = 100-37 = 63 g
Remember the density of water is 1 g/mL thus 63 g of water equal to 63 mL so we can get the molarity of HCl solution
Molarity of HCl = mol/volume = 1.015 mol/0.063 L = 16.11 M
You can use this formula for the dilution calculation ( this calculation is made if you want to prepare 0.1 M HCl 1000 mL)
M1V1=M2V2
16.11.V1 = 0.1 x 1000
V1 = 6.21 mL
So just pipette 6.21 mL of HCl 37% and than dilute it by adding water until the volume reach 1000 mL