0.1 N H2S04 solution Formation

Liquid solutions have many problems . if in this have any mistake plz tell me 　 Two Things are important to making Liquid solutions 1. %age purity of Chemical 2. Specific Gravity or density of Chemical
These informations are printed on Bottles of Chemical in LabThen for Normal Solution to determine the equivalant mass of Chemical %% Now Start %% : 
The specific gravity for H2SO4 =1.84%age purity of H2SO4 = 97 % Gram-formula weight of H2SO4 = 98/2 = 49 gGrams of compound needed = (N desired)(equivalent mass)(volume in liters desired). Substituting the above numbers into the equation, we get: 
grams of compound needed = (0.1 N)(49)(1 liters) = 4.9 grams.Volume of concentrated acid needed = (grams of acid needed)/(percent concentration x specific gravity)volume of concentrated acid needed = (4.9 grams)/(0.97 x 1.84) = 8.74 mL

 Note:If you took 8.74 mL of concentrated sulfuric acid and diluted it to 1 L , you would have a 0.1 N H2SO4 solution.